Extend dplyr::recode() method from dplyr to works with labelled vectors.

# S3 method for haven_labelled
recode(
.x,
...,
.default = NULL,
.missing = NULL,
.keep_value_labels = TRUE,
.combine_value_labels = FALSE,
.sep = " / "
)

## Arguments

.x

A vector to modify

...

<dynamic-dots> Replacements. For character and factor .x, these should be named and replacement is based only on their name. For numeric .x, these can be named or not. If not named, the replacement is done based on position i.e. .x represents positions to look for in replacements. See examples.

When named, the argument names should be the current values to be replaced, and the argument values should be the new (replacement) values.

All replacements must be the same type, and must have either length one or the same length as .x.

.default

If supplied, all values not otherwise matched will be given this value. If not supplied and if the replacements are the same type as the original values in .x, unmatched values are not changed. If not supplied and if the replacements are not compatible, unmatched values are replaced with NA.

.default must be either length 1 or the same length as .x.

.missing

If supplied, any missing values in .x will be replaced by this value. Must be either length 1 or the same length as .x.

.keep_value_labels

If TRUE, keep original value labels. If FALSE, remove value labels.

.combine_value_labels

If TRUE, will combine original value labels to generate new value labels. Note that unexpected results could be obtained if a same old value is recoded into several different new values.

.sep

Separator to be used when combining value labels.

dplyr::recode()

## Examples

x <- labelled(1:3, c(yes = 1, no = 2))
x
#> <labelled<integer>[3]>
#> [1] 1 2 3
#>
#> Labels:
#>  value label
#>      1   yes
#>      2    no
dplyr::recode(x, 3 = 2L)
#> <labelled<integer>[3]>
#> [1] 1 2 2
#>
#> Labels:
#>  value label
#>      1   yes
#>      2    no

# do not keep value labels
dplyr::recode(x, 3 = 2L, .keep_value_labels = FALSE)
#> [1] 1 2 2

# be careful, changes are not of the same type (here integers), NA are created
dplyr::recode(x, 3 = 2)
#> Warning: Unreplaced values treated as NA as .x is not compatible.
#> Please specify replacements exhaustively or supply .default.
#> <labelled<double>[3]>
#> [1] NA NA  2
#>
#> Labels:
#>  value label
#>      1   yes
#>      2    no

# except if you provide .default or new values for all old values
dplyr::recode(x, 1 = 1, 2 = 1,3 = 2)
#> <labelled<double>[3]>
#> [1] 1 1 2
#>
#> Labels:
#>  value label
#>      1   yes
#>      2    no

# if you change the type of the vector (here transformed into character)
# value labels are lost
dplyr::recode(x, 3 = "b", .default = "a")
#> Warning: The type of .x has been changed and value labels attributes have been lost.
#> [1] "a" "a" "b"

# use .keep_value_labels = FALSE to avoid a warning
dplyr::recode(x, 3 = "b", .default = "a", .keep_value_labels = FALSE)
#> [1] "a" "a" "b"

# combine value labels
x <- labelled(1:4, c("strongly agree" = 1, "agree" = 2, "disagree" = 3, "strongly disagree" = 4))
dplyr::recode(x, 1 = 1L, 2 = 1L, 3 = 2L, 4 = 2L, .combine_value_labels = TRUE)
#> <labelled<integer>[4]>
#> [1] 1 1 2 2
#>
#> Labels:
#>  value                        label
#>      1       strongly agree / agree
#>      2 disagree / strongly disagree
dplyr::recode(x, 2 = 1L, 4 = 3L, .combine_value_labels = TRUE)
#> <labelled<integer>[4]>
#> [1] 1 1 3 3
#>
#> Labels:
#>  value                        label
#>      1       strongly agree / agree
#>      3 disagree / strongly disagree
dplyr::recode(x, 2 = 1L, 4 = 3L, .combine_value_labels = TRUE, .sep = " or ")
#> <labelled<integer>[4]>
#> [1] 1 1 3 3
#>
#> Labels:
#>  value                         label
#>      1       strongly agree or agree
#>      3 disagree or strongly disagree
dplyr::recode(x, 2 = 1L, .default = 2L, .combine_value_labels = TRUE)
#> <labelled<integer>[4]>
#> [1] 2 1 2 2
#>
#> Labels:
#>  value                                         label
#>      1                                         agree
#>      2 strongly agree / disagree / strongly disagree

# example when combining some values without a label
y <- labelled(1:4, c("strongly agree" = 1))
dplyr::recode(y, 2 = 1L, 4 = 3L, .combine_value_labels = TRUE)
#> <labelled<integer>[4]>
#> [1] 1 1 3 3
#>
#> Labels:
#>  value          label
#>      1 strongly agree